If the sides of a right triangle are in Arithmetic Progression and its area is equal to 150 m², we can affirm that the perimeter of this triangle is

A person hired a gardener to mow the lawn of their residence. The time spent by this gardener to mow the grass in an area of 40 m² was 80 minutes. The figure represents the lawn, indicating the areas where the work has already been done and where the grass still needs to be trimmed. Consider that the gardener maintains the same pace of work in the rest of the lawn. How many minutes will the gardener take to complete the remaining lawn mowing?

To solve this question, we need to understand the relationship between the lawn area and the time the gardener takes to mow it. We know that the gardener takes 80 minutes to mow 40 m² of grass. This means he takes 2 minutes to mow 1 m² (80/40). If the remaining lawn has a larger area, the gardener will take more time to mow it. For example, if the remaining lawn has an area of 160 m², the gardener will take 320 minutes to mow it (160*2), which is the correct answer. The other alternatives are smaller than 320, which means the gardener would not have enough time to mow all the remaining lawn.

Joana decided to create a flowerbed in her garden. She planned two flowerpots in different shapes, the first in the shape of a rectangle and the second in the shape of a semicircle. The flowerpots will be connected, with one edge of the rectangle coinciding with the diameter of the semicircle. The measurements of the rectangle are 3 meters wide and 5 meters long, and the diameter of the semicircle is equal to the width of the rectangle (3 meters). Considering this structure, answer: a) What is the area of the rectangular flowerpot? b) What is the area of the semicircular flowerpot? c) What is the total area of the flowerbed?

The city hall of a city made a project to partially grass one of its squares. The square is rectangular, with a length of 70 m and a width of 40 m, and is represented in the figure by the rectangle ABCD. It will be covered with grass in the shaded parts, as shown in the scheme below: Knowing that M and N are the midpoints of AB and CD, respectively, the area to be grassed corresponds to

To solve this question, we need to calculate the total area of the square and subtract the area that will not be grassed. The total area of the square is calculated by multiplying the length by the width (70m * 40m = 2800m²). The area that will not be grassed is a smaller rectangle in the center of the square. Since M and N are midpoints, the length and width of this rectangle are half of the length and width of the square, respectively (35m * 20m = 700m²). By subtracting the area that will not be grassed from the total area of the square, we get the area to be grassed (2800m² - 700m² = 2100m²). Therefore, the correct answer is 2100m².

A plot of land has the shape of a trapezoid with bases of 20m and 14m, and a height of 11m. In this plot of land, a rectangular swimming pool of 8m by 5m was built. The rest of the land was covered with grass. The grassed area of the plot will be

To solve this question, we need to follow these steps: 1. Calculate the area of the trapezoid plot. To calculate the area of a trapezoid, we use the formula A = ((B+b)*h)/2, where A is the area, B and b are the larger and smaller bases, and h is the height. In this case, we have B = 20m, b = 14m, and h = 11m. Substituting the values, we have: A_plot = ((20+14)*11)/2 A_plot = (34*11)/2 A_plot = 374/2 A_plot = 187m² 2. Calculate the area of the rectangular pool. To calculate the area of a rectangle, we use the formula A = L*W, where A is the area, L is the length, and W is the width. In this case, we have L = 8m and W = 5m. Substituting the values, we have: A_pool = 8*5 A_pool = 40m² 3. Calculate the grassed area of the plot. The grassed area is the difference between the plot area and the pool area. So, we have: A_grassed = A_plot - A_pool A_grassed = 187m² - 40m² A_grassed = 147m² Therefore, the grassed area of the plot is 147m².

Question bank: Area: Composite Figures

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