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Question about VSEPR and Bond Hybridization

Subject Chemistry

Chemistry

Source Originais Teachy

Originais Teachy

Topic VSEPR and Bond Hybridization

VSEPR and Bond Hybridization

Difficulty Hard

Hard

(Originais Teachy 2023) - Question Hard of Chemistry

Consider a molecule of XeF4, which is an example of a molecule that exhibits the concept of bond hybridization. Using your understanding of the Valence Shell Electron Pair Repulsion (VSEPR) theory and bond hybridization, explain why the XeF4 molecule has a square planar geometry and the type of hybrid orbitals it forms.

The XeF4 molecule has a square planar geometry due to the arrangement of its electron pairs according to VSEPR theory, and it forms sp3d2 hybrid orbitals due to the need to accommodate six electron pairs around the central xenon atom.

The XeF4 molecule has a tetrahedral geometry due to the arrangement of its electron pairs according to VSEPR theory, and it forms sp3 hybrid orbitals due to the need to accommodate four electron pairs around the central xenon atom.

The XeF4 molecule has a trigonal bipyramidal geometry due to the arrangement of its electron pairs according to VSEPR theory, and it forms sp3d hybrid orbitals due to the need to accommodate five electron pairs around the central xenon atom.

The XeF4 molecule has a octahedral geometry due to the arrangement of its electron pairs according to VSEPR theory, and it forms sp3d2 hybrid orbitals due to the need to accommodate six electron pairs around the central xenon atom.

The XeF4 molecule has a linear geometry due to the arrangement of its electron pairs according to VSEPR theory, and it forms sp hybrid orbitals due to the need to accommodate two electron pairs around the central xenon atom.

Answer sheet:

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